JEE Main 2022PhysicsMotion In One DimensionMediumMCQ

JEE Main 2022 — Motion In One Dimension Question with Solution

JEE Main 2022 (28 Jun Shift 1)

Question

Motion of a particle in x-y plane is described by a set of following equations x=4sinπ2-ωt m and y=4sinωt m. The path of the particle will be

Choose an option

Show full solutionCorrect option: A
Correct answer
Acircular

Step-by-step explanation

x=4sinπ2-ωt=4cosωt,

y=4sinωt

Clearly,   x2+y2=4cosωt2+4sinωt2⇒x2+y2=16

Hence, the path covered by particle is a circle.

Practice this on the real CBT interface

Solve this JEE Main question (and the rest of the Motion In One Dimension chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.

Solve interactively →

About this question

This is a previous-year question from JEE Main 2022, covering the Motion In One Dimension chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.