JEE Main 2018PhysicsMotion In One DimensionMediumMCQ

JEE Main 2018 — Motion In One Dimension Question with Solution

JEE Main 2018 (15 Apr)

Question

The velocity time graphs of a car and a scooter are shown in the figure. (i) The difference between the distance travelled by the car and the scooter in 15 s and (ii) the time at which the car will catch up with the scooter are, respectively.

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Show full solutionCorrect option: A
Correct answer
A112.5 m and 22.5 s

Step-by-step explanation

Distance travelled by car in 15 s =12×45×15×=6752 m. Distance travelled by scooter in 15 s=30 ×15=450. Let car catches scooter in time t
difference between the distance travelled by car and scooter in 15 s in⇒ 450−6752=112.5  m
⇒6752+45t-15=30t
337.5+45t-675=30t  ⇒15 t=337.5 
⇒t=22.5 s.

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About this question

This is a previous-year question from JEE Main 2018, covering the Motion In One Dimension chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.