JEE Main 2019PhysicsMotion In One DimensionEasyMCQ

JEE Main 2019 — Motion In One Dimension Question with Solution

JEE Main 2019 (09 Apr Shift 2)

Question

The position vector of a particle changes with time according to the relation r→t=15t2i^+4-20t2j^. What is the magnitude of the acceleration at t=1?

Choose an option

Show full solutionCorrect option: D
Correct answer
D50

Step-by-step explanation

r→=15t2i^+4-20t2j^
v→=30 ti^-40t j^
a→=30 i^-40j^
At t=1 ,
a→=30 i^-40j^
a→=50

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About this question

This is a previous-year question from JEE Main 2019, covering the Motion In One Dimension chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.