JEE Main 2021PhysicsMotion In Two DimensionsHardMCQ

JEE Main 2021 — Motion In Two Dimensions Question with Solution

JEE Main 2021 (24 Feb Shift 2)

Question

A particle is projected with velocity v0 along x-axis. A damping force is acting on the particle which is proportional to the square of the distance from the origin i.e. ma=-αx2. The distance at which the particle stops:

Choose an option

Show full solutionCorrect option: B
Correct answer
B3mv022α13

Step-by-step explanation

F=-αx2

ma=-αx2

a=-αx2 m

vdvdx=-αmx2

∫v00vdv=∫0x-αmx2dx

v22v00=-αmx330x

-v022=-αmx33

x=3mv022α13

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About this question

This is a previous-year question from JEE Main 2021, covering the Motion In Two Dimensions chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.