JEE Main 2020PhysicsMotion In Two DimensionsEasyMCQ

JEE Main 2020Motion In Two Dimensions Question with Solution

JEE Main 2020 (09 Jan Shift 2)

Question

A spring mass system (mass m, spring constant k and natural length l ) rests in equilibrium on a horizontal disc. The free end of the spring is fixed at the centre of the disc. If the disc together with spring mass system rotates about it's axis with an angular velocity ω,k>>mω2 the relative change in the length of the spring is best given by the option:

Choose an option

Show full solutionCorrect option: C
Correct answer
Cmω2k

Step-by-step explanation

mω2l0+x=kx
l0x+1=kmω2
x=l0mω2k-mω2
kmω2
So, xl0 is equal to mω2k

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About this question

This is a previous-year question from JEE Main 2020, covering the Motion In Two Dimensions chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.