JEE Main 2012 — Nuclear Physics Question with Solution
JEE Main 2012 (Offline)
Question
Assume that a neutron breaks into a proton and an electron. The energy released during this process is (Mass of neutron mass of proton mass of electron
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Show full solutionCorrect option: A
Correct answer
A
Step-by-step explanation
$\begin{aligned}
\Delta m & =\left(m_p+m_e\right)-m_n \\
& =9 \times 10^{-31} \mathrm{~kg}.
\end{aligned}$
Energy released joules
$\begin{aligned}
& =\frac{9 \times 10^{-31} \times\left(3 \times 10^8\right)^2}{1.6 \times 10^{-13}} \mathrm{MeV} \\
& =0.73 \mathrm{~MeV} .
\end{aligned}$
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This is a previous-year question from JEE Main 2012, covering the Nuclear Physics chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.