JEE Main 2024PhysicsNuclear PhysicsEasyNumerical

JEE Main 2024 — Nuclear Physics Question with Solution

JEE Main 2024 (01 Feb Shift 1)

Question

The radius of a nucleus of mass number 64 is 4.8 fermi. Then the mass number of another nucleus having radius of 4 fermi is 1000x, where x is _________.

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Show full solutionCorrect answer: 27
Correct answer
27

Step-by-step explanation

Radius of a nucleus is given by, R=R0 A1/3.

Therefore, R3∝A

⇒4.843=64A

⇒64 A=(1.2)3

⇒64A=1.44×1.2

⇒A=641.44×1.2=1000x

⇒x=144×1264=27

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About this question

This is a previous-year question from JEE Main 2024, covering the Nuclear Physics chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.