JEE Main 2021 — Rotational Motion Question with Solution
From: JEE Main 2021 (Online) 1st September Evening Shift
Question
A 2 kg steel rod of length 0.6 m is clamped on a table vertically at its lower end and is free to rotate in vertical plane. The upper end is pushed so that the rod falls under gravity, ignoring the friction due to clamping at its lower end, the speed of the free end of rod when it passes through its lowest position is ____________ ms1. (Take g = 10 ms2)
Enter your answer
Show full solutionCorrect answer: 6
Correct answer
6
Step-by-step explanation
by energy conservation
As we know the relation between the linear speed and angular speed,
= 6 m/s
Hence, the speed of the free end of the rod when it passes through its lowest position is 6 m/s.
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This is a previous-year question from JEE Main 2021, covering the Rotational Motion chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.