JEE Main 2023PhysicsRotational MotionEasyNumerical

JEE Main 2023 — Rotational Motion Question with Solution

JEE Main 2023 (08 Apr Shift 1)

Question

The moment of inertia of a semicircular ring about an axis, passing through the center and perpendicular to the plane of ring, is 1x MR2, where R is the radius and M is the mass of the semicircular ring. The value of x will be _______.

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Correct answer
1

Step-by-step explanation

The moment of inertia of a semicircular ring about a line perpendicular to the plane of the ring and passing through its centre is given as I=MR2, where m and R are the mass and radius of the ring. Comparing the given value

.I= MR2=1xMR2

⇒x=1

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About this question

This is a previous-year question from JEE Main 2023, covering the Rotational Motion chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.