JEE Main 2024PhysicsRotational MotionEasyNumerical

JEE Main 2024 — Rotational Motion Question with Solution

JEE Main 2024 (29 Jan Shift 1)

Question

A cylinder is rolling down on an inclined plane of inclination 60°. Its acceleration during rolling down will be x3 m s-2, where x= _______(use g=10 m s-2).

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Show full solutionCorrect answer: 10
Correct answer
10

Step-by-step explanation

For rolling motion, the acceleration of the cylinder along the inclined plane can be expressed as

a=gsinθ1+IcmMR2   ...1

The moment of inertia of the cylinder can be written as

Icm=12MR2   ...2

From equations (1) and (2), it follows that

a=gsinθ1+12=2×10×323=103 m s-2

Therefore, x=10.

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About this question

This is a previous-year question from JEE Main 2024, covering the Rotational Motion chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.