JEE Main 2019 — Rotational Motion Question with Solution
From: JEE Main 2019 (Online) 11th January Evening Slot
Question
The magnitude of torque on a particle of mass 1 kg is 2.5 Nm about the origin. If the force acting on it is 1 N, and the distance of the particle from the origin is 5m, the angle between the force and the position vector is (in radians) :
Choose an option
Show full solutionCorrect option: B
Correct answer
B
Step-by-step explanation
2.5 = 1 5 sin
sin = 0.5 =
=
sin = 0.5 =
=
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This is a previous-year question from JEE Main 2019, covering the Rotational Motion chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.