JEE Main 2021PhysicsRotational MotionTorqueeasyNumerical

JEE Main 2021Rotational Motion Question with Solution

From: JEE Main 2021 (Online) 16th March Morning Shift

Question

Consider a frame that is made up of two thin massless rods AB and AC as shown in the figure. A vertical force of magnitude 100 N is applied at point A of the frame.

JEE Main 2021 (Online) 16th March Morning Shift Physics - Rotational Motion Question 124 English
Suppose the force is resolved parallel to the arms AB and AC of the frame.

The magnitude of the resolved component along the arm AC is xN.

The value of x, to the nearest integer, is ___________.

[Given : sin(35) = 0.573, cos(35) = 0.819

sin(110) = 0.939, cos(110) = 0.342 J

This question includes a diagram. The text above accompanies the figure.

Enter your answer

Show full solutionCorrect answer: 81.9
Correct answer
81.9

Step-by-step explanation

JEE Main 2021 (Online) 16th March Morning Shift Physics - Rotational Motion Question 124 English Explanation
Component along AC

= 100 cos 35 N

= 100 0.819 N

= 81.9 N

82 N

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About this question

This is a previous-year question from JEE Main 2021, covering the Rotational Motion chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.