JEE Main 2019 — Rotational Motion Question with Solution
From: JEE Main 2019 (Online) 10th April Morning Slot
Question
A thin disc of mass M and radius R has mass
per unit area (r) = kr2 where r is the distance
from its centre. Its moment of inertia about an
axis going through its centre of mass and
perpendicular to its plane is :
Choose an option
Show full solutionCorrect option: C
Correct answer
C
Step-by-step explanation
Mass of Disc
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This is a previous-year question from JEE Main 2019, covering the Rotational Motion chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.