JEE Main 2019 — Rotational Motion Question with Solution
From: JEE Main 2019 (Online) 9th April Morning Slot
Question
A stationary horizontal disc is free to rotate
about its axis. When a torque is applied on it,
its kinetic energy as a function of , where
is the angle by which it has rotated, is given as
k2. If its moment of inertia is I then the
angular acceleration of the disc is :
Choose an option
Show full solutionCorrect option: D
Correct answer
D
Step-by-step explanation
Kinetic energy KE =
.... (A)
Differentiate (A) wrt time
.... (A)
Differentiate (A) wrt time
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This is a previous-year question from JEE Main 2019, covering the Rotational Motion chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.