JEE Main 2018PhysicsSemiconductorsEasyMCQ

JEE Main 2018 — Semiconductors Question with Solution

JEE Main 2018 (15 Apr)

Question

In a common emitter configuration with suitable bias, it is given that RL is the load resistance and RBE is small-signal dynamic resistance (input side). Then, voltage gain, current gain and power gain are given, respectively, by: β is current gain, IB, IC and IE are respectively base, collector, and emitter currents.

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Correct answer
AβRLRBE,ΔICΔIB,β2RLRBE

Step-by-step explanation

For a common emitter configuration, current gain, β=ΔICΔIB. Voltage gain is the ratio of output voltage to the input voltage. It is given as, AV=ΔVCE RBEΔIB=βRLRBE (Since from Ohm's law, RL=∆VCE∆IB). Power gain AP=βAV=β2RLRBE.

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About this question

This is a previous-year question from JEE Main 2018, covering the Semiconductors chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.