JEE Main 2026 — Thermal Properties of Matter Question with Solution
JEE Main 2026 (28 January Shift 1)
Question
10 kg of ice at is added to 100 kg of water to lower its temperature from 25 . Consider no heat exchange to surroundings. The decrement to the temperature of water is .
(specific heat of ice , specific heat of water , latent heat of fusion of ice )
(specific heat of ice , specific heat of water , latent heat of fusion of ice )
Choose an option
Show full solutionCorrect option: D
Correct answer
D10
Step-by-step explanation
Heat available from water cooling 25°C to 0°C: J.
Heat to warm ice from -10°C to 0°C: J.
Heat to melt ice at 0°C: J.
Total needed: J.
Since available heat exceeds required heat, all ice melts. Remaining heat: J
warms 110 kg water: °C.
Final temperature: 15°C.
Decrement in water temperature: °C.
Heat to warm ice from -10°C to 0°C: J.
Heat to melt ice at 0°C: J.
Total needed: J.
Since available heat exceeds required heat, all ice melts. Remaining heat: J
warms 110 kg water: °C.
Final temperature: 15°C.
Decrement in water temperature: °C.
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This is a previous-year question from JEE Main 2026, covering the Thermal Properties of Matter chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.