JEE Main 2015 — Thermodynamics Question with Solution
JEE Main 2015 (10 Apr Online)
Question
An ideal gas goes through a reversible cycle has the V - T diagram shown below. Process are adiabatic.

The corresponding P - V diagram for the process is (all figures are schematic and not drawn to scale) :

The corresponding P - V diagram for the process is (all figures are schematic and not drawn to scale) :
Choose an option
Show full solutionCorrect option: A
Correct answer
A

Step-by-step explanation
Is an adiabatic process
as T increase V decreases at non-uniform rate
In process P = constant as
In process constant s
But since slope of V - T graph
since slope of ab < slope of cd
Also in adiabatic process as T is increasing V in decreasing
P is increasing, so P - V diagram is as below

as T increase V decreases at non-uniform rate
In process P = constant as
In process constant s
But since slope of V - T graph
since slope of ab < slope of cd
Also in adiabatic process as T is increasing V in decreasing
P is increasing, so P - V diagram is as below

Practice this on the real CBT interface
Solve this JEE Main question (and the rest of the Thermodynamics chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.
Solve interactively →About this question
This is a previous-year question from JEE Main 2015, covering the Thermodynamics chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.