JEE Main 2019 — Thermodynamics Question with Solution
JEE Main 2019 (11 Jan Shift 1)
Question
A rigid diatomic ideal gas undergoes an adiabatic process at room temperature. The relation between temperature and volume for this process is constant, then is:
Choose an option
Show full solutionCorrect option: B
Correct answer
B
Step-by-step explanation
Equation of adiabatic change is
Put , we get:
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This is a previous-year question from JEE Main 2019, covering the Thermodynamics chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.