JEE Main 2021PhysicsThermodynamicsEasyMCQ

JEE Main 2021 — Thermodynamics Question with Solution

JEE Main 2021 (25 Jul Shift 1)

Question

A monoatomic ideal gas, initially at temperature T1 is enclosed in a cylinder fitted with a frictionless piston. The gas is allowed to expand adiabatically to a temperature T2 by releasing the piston suddenly. If l1 and l2 are the lengths of the gas column, before and after the expansion respectively, then the value of T1 T2 will be:

Choose an option

Show full solutionCorrect option: B
Correct answer
Bl2l123

Step-by-step explanation

PVr= constant

TVr-1= constant

T(ℓ)53-1= constant

T1 T2=ℓ2ℓ12/3

Practice this on the real CBT interface

Solve this JEE Main question (and the rest of the Thermodynamics chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.

Solve interactively →

About this question

This is a previous-year question from JEE Main 2021, covering the Thermodynamics chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.