JEE Main 2022PhysicsThermodynamicsMediumMCQ

JEE Main 2022 — Thermodynamics Question with Solution

JEE Main 2022 (27 Jul Shift 2)

Question

In 1st  case, Carnot engine operates between temperatures 300 K and 100 K. In 2nd  case, as shown in the figure, a combination of two engines is used. The efficiency of this combination (in 2nd  case) will be :

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Show full solutionCorrect option: A
Correct answer
Asame as the 1st  case

Step-by-step explanation

The efficiency of a Carnot engine operating between two temperatures is given by η=1-TLTH

For the first case : η=1-100300=23

For the second case : ηnet =η1+η2-η1η2

η1=1-200300=13

η2=1-100200=12

ηnet =13+12-16=23

η(first case)=η(second case)

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About this question

This is a previous-year question from JEE Main 2022, covering the Thermodynamics chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.