JEE Main 2013 — Thermodynamics Question with Solution
JEE Main 2013 (09 Apr Online)
Question
Figure shows the variation in temperature with the amount of heat supplied in an isobaric process corresponding to a monoatomic , diatomic and a polyatomic gas. The initial state of all the gases are the same and the scales for the two axes coincide. Ignoring vibrational degrees of freedom, the lines and respectively correspond to :
Choose an option
Show full solutionCorrect option: B
Correct answer
B, and
Step-by-step explanation
On giving same amount of heat at constant pressure, there is no change in temperature for mono, dia and polyatomic.
or
Practice this on the real CBT interface
Solve this JEE Main question (and the rest of the Thermodynamics chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.
Solve interactively →About this question
This is a previous-year question from JEE Main 2013, covering the Thermodynamics chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.