JEE Main 2024PhysicsThermodynamicsMediumMCQ

JEE Main 2024 — Thermodynamics Question with Solution

JEE Main 2024 (29 Jan Shift 1)

Question

A thermodynamic system is taken from an original state A to an intermediate state B by a linear process as shown in the figure. Its volume is then reduced to the original value from B to C by an isobaric process. The total work done by the gas from A to B and B to C would be :

Choose an option

Show full solutionCorrect option: D
Correct answer
D800 J

Step-by-step explanation

Work done during the path A→B can be written as WAB=12(8000+4000) dyne cm-2×1 N105 dyne×1 cm210-4 m2×7-3 m3=2400 J

The work done during the process B→C is given by

WBC=4000 dyne cm-2×1 N105 dyne×1 cm210-4 m2×3-7 m3=-1600 J

Hence, the total work done is given by

W=WAB+WBC=2400 J-1600 J=800 J

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About this question

This is a previous-year question from JEE Main 2024, covering the Thermodynamics chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.