JEE Main 2020PhysicsThermodynamicsHardNumerical

JEE Main 2020Thermodynamics Question with Solution

JEE Main 2020 (02 Sep Shift 1)

Question

An engine takes in 5 moles of air at 20 °C and 1 atm, and compresses it adiabatically to 1/10th of the original volume. Assuming air to be a diatomic ideal gas made up of rigid molecules, the change in its internal energy during this process comes out to be XkJ. The value of X to the nearest integer is: 

Enter your answer

Show full solutionCorrect answer: 46
Correct answer
46

Step-by-step explanation

T1V1γ-1=T2V2γ-1

T2=T1V1V2γ-1

=T1(10)75-1

T2=T1(10)2/5

ΔV=52nR;52×5×3102/5-1(293)

6256×1.5×293=461440

46ks

Practice this on the real CBT interface

Solve this JEE Main question (and the rest of the Thermodynamics chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.

Solve interactively →

About this question

This is a previous-year question from JEE Main 2020, covering the Thermodynamics chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.