JEE Main 2026 — Units and Dimensions Question with Solution
JEE Main 2026 (21 January Shift 2)
Question
Keeping the significant figures in view, the sum of the physical quantities and 0.123 m is :
Choose an option
Show full solutionCorrect option: A
Correct answer
A205.3 m
Step-by-step explanation
When adding measurements, the result must be limited to the least number of decimal places among all quantities.
The measurements are: 52.01 m (2 decimal places), 153.2 m (1 decimal place), and 0.123 m (3 decimal places).
The limiting factor is 1 decimal place.
Calculating the sum: 52.01 + 153.2 + 0.123 = 205.333 m.
Rounding to 1 decimal place gives 205.3 m, which is option (1).
The measurements are: 52.01 m (2 decimal places), 153.2 m (1 decimal place), and 0.123 m (3 decimal places).
The limiting factor is 1 decimal place.
Calculating the sum: 52.01 + 153.2 + 0.123 = 205.333 m.
Rounding to 1 decimal place gives 205.3 m, which is option (1).
Practice this on the real CBT interface
Solve this JEE Main question (and the rest of the Units and Dimensions chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.
Solve interactively →About this question
This is a previous-year question from JEE Main 2026, covering the Units and Dimensions chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.