JEE Main 2021PhysicsWave OpticsEasyMCQ

JEE Main 2021 — Wave Optics Question with Solution

JEE Main 2021 (26 Feb Shift 1)

Question

In a Young's double slit experiment two slits are separated by 2 mm and the screen is placed one meter away. When a light of wavelength 500 nm is used, the fringe separation will be :

Choose an option

Show full solutionCorrect option: D
Correct answer
D0.25 mm

Step-by-step explanation

β=λDd=500×10-9×12×10-3

β=52×10-4 m=2.5×10-1 mm

b=0.25 mm

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About this question

This is a previous-year question from JEE Main 2021, covering the Wave Optics chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.