JEE Main 2020 — Wave Optics Question with Solution
From: JEE Main 2020 (Online) 2nd September Morning Slot
Question
Interference fringes are observed on a screen
by illuminating two thin slits 1 mm apart with a
light source ( = 632.8 nm). The distance
between the screen and the slits is 100 cm. If
a bright fringe is observed on a screen at a
distance of 1.27 mm from the central bright
fringe, then the path difference between the
waves, which are reaching this point from the
slits is close is
Choose an option
Show full solutionCorrect option: A
Correct answer
A1.27 m
Step-by-step explanation
y =
n =
= = 2
Path difference x = n
= 2 632.8 nm
= 1265.6 nm
= 1.27 m
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This is a previous-year question from JEE Main 2020, covering the Wave Optics chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.