JEE Main 2019 — Wave Optics Question with Solution
From: JEE Main 2019 (Online) 10th January Morning Slot
Question
In a Young’s double slit experiment with slit separation 0.1 mm, one observes a bright fringe at angle by using light of wavelength 1. When the light of wavelength 2 is used a bright fringe is seen at the same angle in the same set up. Given that 1 and 2 are in visible range (380 nm to 740 nm), their values are -
Choose an option
Show full solutionCorrect option: B
Correct answer
B625 nm, 500 nm
Step-by-step explanation
Path difference = d sin d
= 0.1 mm = 2500nm
or bright fringe, path difference must be integral multiple of .
2500 = n1 = m2
1 = 625 (from n = 4), 2 = 500 (from m = 5)
= 0.1 mm = 2500nm
or bright fringe, path difference must be integral multiple of .
2500 = n1 = m2
1 = 625 (from n = 4), 2 = 500 (from m = 5)
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This is a previous-year question from JEE Main 2019, covering the Wave Optics chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.