JEE Main 2019PhysicsWave OpticsHuygens Principle And Interference Of LightmediumMCQ

JEE Main 2019Wave Optics Question with Solution

From: JEE Main 2019 (Online) 10th January Morning Slot

Question

In a Young’s double slit experiment with slit separation 0.1 mm, one observes a bright fringe at angle by using light of wavelength 1. When the light of wavelength 2 is used a bright fringe is seen at the same angle in the same set up. Given that 1 and 2 are in visible range (380 nm to 740 nm), their values are -

Choose an option

Show full solutionCorrect option: B
Correct answer
B625 nm, 500 nm

Step-by-step explanation

Path difference = d sin d

= 0.1 mm = 2500nm

or bright fringe, path difference must be integral multiple of .

   2500 = n1 = m2

   1 = 625 (from n = 4), 2 = 500 (from m = 5)

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About this question

This is a previous-year question from JEE Main 2019, covering the Wave Optics chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.