JEE Main 2016PhysicsWave OpticsHuygens Principle And Interference Of LightmediumMCQ

JEE Main 2016Wave Optics Question with Solution

From: JEE Main 2016 (Online) 9th April Morning Slot

Question

In Young’s double slit experiment, the distance between slits and the screen is 1.0 m and monochromatic light of 600 nm is being used. A person standing near the slits is looking at the fringe pattern. When the separation between the slits is varied, the interference pattern disappears for a particular distance d0 between the slits. If the angular resolution of the eye is , the value of d0 is close to :

Choose an option

Show full solutionCorrect option: B
Correct answer
B2 mm

Step-by-step explanation

We know,

Fringe width, =

JEE Main 2016 (Online) 9th April Morning Slot Physics - Wave Optics Question 128 English Explanation

From image,

=

   =

  d0 =

=

= 2.06 103

2 mm

Practice this on the real CBT interface

Solve this JEE Main question (and the rest of the Wave Optics chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.

Solve interactively →

About this question

This is a previous-year question from JEE Main 2016, covering the Wave Optics chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.