JEE Main 2020PhysicsWave OpticsHuygens Principle And Interference Of LighteasyNumerical

JEE Main 2020Wave Optics Question with Solution

From: JEE Main 2020 (Online) 9th January Evening Slot

Question

In a Young's double slit experiment 15 fringes are observed on a small portion of the screen when light of wavelength 500 nm is used. Ten fringes are observed on the same section of the screen when another light source of wavelength is used. Then the value of is (in nm) __________.

Enter your answer

Show full solutionCorrect answer: 750
Correct answer
750

Step-by-step explanation

The length of the screen used portion for 15 fringes, and also for ten fringes

15 500 = 10

15 × 50 =

= 750 nm

Practice this on the real CBT interface

Solve this JEE Main question (and the rest of the Wave Optics chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.

Solve interactively →

About this question

This is a previous-year question from JEE Main 2020, covering the Wave Optics chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.