JEE Main 2022PhysicsWaves and SoundMediumNumerical

JEE Main 2022Waves and Sound Question with Solution

JEE Main 2022 (24 Jun Shift 2)

Question

Two travelling waves of equal amplitudes and equal frequencies move in opposite directions along a string. They interfere to produce a stationary wave whose equation is given by y=10cosπxsin2πtTcm. The amplitude of the particle at x=43 cm will be _____ cm.

Enter your answer

Show full solutionCorrect answer: 5
Correct answer
5

Step-by-step explanation

Amplitude is the maximum displacement from the mean position, for that

sin2πtT=1

Therefore, A=10cos43π=10×12= 5 cm

Practice this on the real CBT interface

Solve this JEE Main question (and the rest of the Waves and Sound chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.

Solve interactively →

About this question

This is a previous-year question from JEE Main 2022, covering the Waves and Sound chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.