JEE Main 2022PhysicsWaves and SoundMediumMCQ

JEE Main 2022Waves and Sound Question with Solution

JEE Main 2022 (29 Jun Shift 1)

Question

A longitudinal wave is represented by y=10sin2πnt-xλ cm. The maximum particle velocity will be four times the wave velocity if the determined value of wavelength is equal to

Choose an option

Show full solutionCorrect option: B
Correct answer
B5π

Step-by-step explanation

As we know particle velocity, vp=dydt=10×2πn×cos2πnt-xλ

Therefore, vpmax=20πn

Now as we know, v=λn

As given in the question, 

vpmax=4v20πn=4λnλ=5π

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About this question

This is a previous-year question from JEE Main 2022, covering the Waves and Sound chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.