JEE Main 2019PhysicsWaves and SoundMediumMCQ

JEE Main 2019 — Waves and Sound Question with Solution

JEE Main 2019 (09 Apr Shift 1)

Question

The pressure wave, P=0.01sin⁡1000t-3xN m–2 , corresponds to the sound produced by a vibrating blade on a day when atmospheric temperature is 0°C . On some other day when temperature is T , the speed of sound produced by the same blade and at the same frequency is found to be 336 m s–1 . Approximate value of T is:

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Show full solutionCorrect option: C
Correct answer
C4° C

Step-by-step explanation

at 0°C
y=Asin(1000t-3x)
v1=ωk=10003
at temperature T,v2=336 m/s
v1v2=T1T2

⇒1000336=273T⇒T=277.41K
i.e .T=4.4°C=4°C

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About this question

This is a previous-year question from JEE Main 2019, covering the Waves and Sound chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.