JEE Main 2014PhysicsWaves and SoundMediumMCQ

JEE Main 2014Waves and Sound Question with Solution

JEE Main 2014 (09 Apr Online)

Question

A transverse wave is represented by : y = 1 0 π sin 2 π T t - 2 π λ x  For what value of the wavelength the wave velocity is twice the maximum particle velocity?

Choose an option

Show full solutionCorrect option: A
Correct answer
A40 cm

Step-by-step explanation

wave velocity=nλ

(Vp)max=aω

nλ=2a2πn

λ=2(a)2π

=2.10π.2π

= 40 cm

Practice this on the real CBT interface

Solve this JEE Main question (and the rest of the Waves and Sound chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.

Solve interactively →

About this question

This is a previous-year question from JEE Main 2014, covering the Waves and Sound chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.