JEE Main 2018PhysicsWaves and SoundMediumMCQ

JEE Main 2018 — Waves and Sound Question with Solution

JEE Main 2018 (16 Apr Online)

Question

The end correction of a resonance column is 1 cm. If the shortest length resonating with the tuning fork is 10 cm, the next resonating length should be

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Show full solutionCorrect option: A
Correct answer
A32 cm

Step-by-step explanation

Given: e=1 cm. For first resonance, λ4= l1+e=11 cm. For second resonance, 3λ4= l2+e ⇒ l2=3 ×11-1=32 cm.

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About this question

This is a previous-year question from JEE Main 2018, covering the Waves and Sound chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.