JEE Main 2020PhysicsWaves and SoundMediumMCQ

JEE Main 2020 — Waves and Sound Question with Solution

JEE Main 2020 (07 Jan Shift 2)

Question

A stationary observer receives sound from two identical tuning forks, one of which approaches and the other one recedes with the same speed (much less than the speed of sound). The observer hears 2 beats/sec . The oscillation frequency of each tuning fork is v0=1400 Hz and the velocity of sound in air is 350 m/s . The speed of each tuning fork is close to:

Choose an option

Show full solutionCorrect option: C
Correct answer
C14m/s

Step-by-step explanation


f0CC-V-f0CC+V=2
V=14m/s

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About this question

This is a previous-year question from JEE Main 2020, covering the Waves and Sound chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.