JEE Main 2022PhysicsWaves and SoundEasyMCQ

JEE Main 2022Waves and Sound Question with Solution

JEE Main 2022 (26 Jul Shift 2)

Question

A transverse wave is represented by y=2sinωt-kxcm. The value of wavelength (in cm) for which the wave velocity becomes equal to the maximum particle velocity, will be

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Show full solutionCorrect option: A
Correct answer
A4π

Step-by-step explanation

The given equation is y=2sinωt-kx

The maximum particle velocity =Aω

And the wave velocity =ωk

For wave velocity to be equal to maximum particle velocity

ωk=Aω

k=1 A

Since, k=2πλ

λ=2πA=4π cm.

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About this question

This is a previous-year question from JEE Main 2022, covering the Waves and Sound chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.