JEE Main 2014PhysicsWaves and SoundMediumMCQ

JEE Main 2014Waves and Sound Question with Solution

JEE Main 2014 (06 Apr)

Question

A pipe of length 85 cm is closed from one end. Find the number of possible natural oscillations of air column in the pipe whose frequencies lie below 1250 Hz. The velocity of sound in air is 340 m/s.

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Show full solutionCorrect option: C
Correct answer
C6

Step-by-step explanation

fundamental frequency

       

L=λ4v1=v4L

       

L = λ 2 + λ 4 = 3 λ 4

v2=3v4L

∴   v=oddv4L

Now L = 8 5 cm = 0.85 m

        v=340m/s

          = odd 3 4 0 4 × 0.85

         =odd×100 Hz

Hence possible frequencies below 1250 Hz are

100 Hz, 300 Hz, 500 Hz...........1100 Hz

Hence 6 

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About this question

This is a previous-year question from JEE Main 2014, covering the Waves and Sound chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.