JEE Main 2022PhysicsWork Power EnergyMediumNumerical

JEE Main 2022 — Work Power Energy Question with Solution

JEE Main 2022 (27 Jun Shift 2)

Question

A rolling wheel of 12 kg is on an inclined plane at position P and connected to a mass of 3 kg through a string of fixed length and pulley as shown in figure.
Consider PR as friction free surface.
The velocity of centre of mass of the wheel when it reaches at the bottom Q of the inclined plane PQ will be 12xgh m s-1. The value of x (rounded off to the nearest integer) is _____.

Enter your answer

Show full solutionCorrect answer: 3
Correct answer
3

Step-by-step explanation

If we take the wheel as a ring then its moment of inertia will be, I=Mr2.

Using mechanical energy conservation,

Mgh-mgh=12mv2+12Mv2+12Iω2⇒12gh-3gh=123v2+1212v2+1212r2v2r2

⇒9gh=15v2+12v22

⇒v=23gh=1283gh

Therefore, x=83≃3

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About this question

This is a previous-year question from JEE Main 2022, covering the Work Power Energy chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.