JEE Main 2024PhysicsWork Power EnergyEasyMCQ

JEE Main 2024 — Work Power Energy Question with Solution

JEE Main 2024 (30 Jan Shift 1)

Question

A particle is placed at the point A of a frictionless track ABC as shown in figure. It is gently pushed towards right. The speed of the particle when it reaches the point B is: (Take g=10 m s-2.

Choose an option

Show full solutionCorrect option: B
Correct answer
B10 m s-1

Step-by-step explanation

Applying conservation of mechanical energy between point A & B, we get

KEA+UA=KEB+UB

⇒0+mg(1)=12mv2+mg×0.5

⇒v=g=10 m s-1

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About this question

This is a previous-year question from JEE Main 2024, covering the Work Power Energy chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.