JEE Main 2023PhysicsWork Power EnergyHardNumerical

JEE Main 2023Work Power Energy Question with Solution

JEE Main 2023 (10 Apr Shift 1)

Question

A closed circular tube of average radius 15 cm, whose inner walls are rough, is kept in vertical plane. A block of mass 1 kg just fit inside the tube. The speed of block is 22 m s-1, when it is introduced at the top of tube. After completing five oscillations, the block stops at the bottom region of tube. The work done by the tube on the block is ________ J. (Given g=10 m s-2).

 

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Show full solutionCorrect answer: 245
Correct answer
245

Step-by-step explanation

The data given is 

r=15 cmm=1 kgv=22 m s-1

Total work done by the tube on the block is equal to loss in mechanical energy, 

w=12mv2+mgh

w=12×1×222+1×10×0.3

w=245 J

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About this question

This is a previous-year question from JEE Main 2023, covering the Work Power Energy chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.