JEE Main 2019PhysicsWork Power EnergyMediumMCQ

JEE Main 2019Work Power Energy Question with Solution

JEE Main 2019 (09 Jan Shift 1)

Question

A block of mass m, lying on a smooth horizontal surface, is attached to a spring (of negligible mass) of spring constant k. The other end of the spring is fixed, as shown in the figure. The block is initially at rest in its equilibrium position. If now the block is pulled with a constant force F, the maximum speed of the block is:

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Show full solutionCorrect option: A
Correct answer
AFmk

Step-by-step explanation



When block attains maximum speed net force on m is zero. F=kx

Or x=Fk

From work energy theorem

-12 k Fk2+FFk=12mVmax2

F22k=12mVmax2

Vmax=Fkm

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About this question

This is a previous-year question from JEE Main 2019, covering the Work Power Energy chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.