JEE Main 2017PhysicsWork Power EnergyMediumMCQ

JEE Main 2017 — Work Power Energy Question with Solution

JEE Main 2017 (08 Apr Online)

Question

An object is dropped from a height h from the ground. Every time it hits the ground it loses 50% of its kinetic energy. The total distance covered as t→∞ is:

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Show full solutionCorrect option: A
Correct answer
A3h

Step-by-step explanation

Since the object is dropped from height, thus its potential energy is equal to its kinetic energy.

As per question, kinetic energy after hitting the ground is 12mv′2=12×12 mv2

v′=v2

v=eu   

e=12

H=h1+e21-e2

The total distance covered=h1+121-12=3h

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About this question

This is a previous-year question from JEE Main 2017, covering the Work Power Energy chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.