JEE Main 2014PhysicsWork Power EnergyMediumMCQ

JEE Main 2014Work Power Energy Question with Solution

JEE Main 2014 (19 Apr Online)

Question


A particle is released on a vertical smooth semicircular track from point X so that, OX makes angle θ  from the vertical (see figure). The normal reaction of the track on the particle vanishes at the point Y where OY makes an angle ϕ with the horizontal. Then

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Show full solutionCorrect option: A
Correct answer
Asinϕ=23cosθ

Step-by-step explanation

mgRcosθ-Rsinϕ=12mV2  .......(1)

On losing contact N=0⇒mgsinϕ=mV2R  ......(2)



mgRcosθ-sinϕ=12mgRsinϕ

2cosθ=3sinϕ

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About this question

This is a previous-year question from JEE Main 2014, covering the Work Power Energy chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.