JEE Main 2020 — Work Power Energy Question with Solution

A cricket ball of mass $0.15 \mathrm{kg}$ is thrown vertically up by a bowling machine so that it rises to a maximum height of $20 \mathrm{m}$ after leaving the machine. If the part pushing the ball applies a constant force $\mathrm{F}$ on the ball applies a constant force $F$ on the ball and moves horizontally a distance of $0.2 \mathrm{m}$ while launching the ball, the value of $F(\mathrm{in} N)$ is $\left(g=10 \mathrm{m} {\mathrm{s}}^{-2}\right)$