JEE Main 2018PhysicsWork Power EnergyMediumMCQ

JEE Main 2018 — Work Power Energy Question with Solution

JEE Main 2018 (16 Apr Online)

Question

Two particles of the same mass m are moving in circular orbits because of force, given by F r=-16r-r3. The first particle is at a distance r=1, and the second, at r=4. The best estimate for the ratio of kinetic energies of the first and the second particle is closest to

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Show full solutionCorrect option: C
Correct answer
C6 ×10-2

Step-by-step explanation

Centripetal force is given as Fr=mv2r.

Given in the problem, mV2r=16r+r3  ...i

Kinetic energy is stated as KE0=12mv2.

KE0=1216+r4 (From equationi)

The ratio of kinetic energies of first and second particle is K1K2=16+1216+2562=17272

K1K2 ≃6 ×10-2.

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About this question

This is a previous-year question from JEE Main 2018, covering the Work Power Energy chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.