JEE Main 2026 — Alcohols Phenols and Ethers Question with Solution
JEE Main 2026 (24 January Shift 1)
Question
Consider the following two reactions A and B.
Numerical value of [molar mass of molar mass of ] is .
Numerical value of [molar mass of molar mass of ] is .
Choose an option
Show full solutionCorrect option: D
Correct answer
D46
Step-by-step explanation
Reaction A: Phenol reacts with metallic sodium to produce sodium phenoxide and hydrogen gas.
C₆H₅OH + Na → C₆H₅ONa + ½H₂.
The gas evolved is x = H₂ with molar mass 2 g/mol.
Reaction B: Benzoic acid reacts with sodium bicarbonate to produce sodium benzoate, water, and carbon dioxide.
C₆H₅COOH + NaHCO₃ → C₆H₅COONa + H₂O + CO₂.
The gas evolved is y = CO₂ with molar mass 44 g/mol.
Therefore, molar mass of x + molar mass of y = 2 + 44 = 46.
C₆H₅OH + Na → C₆H₅ONa + ½H₂.
The gas evolved is x = H₂ with molar mass 2 g/mol.
Reaction B: Benzoic acid reacts with sodium bicarbonate to produce sodium benzoate, water, and carbon dioxide.
C₆H₅COOH + NaHCO₃ → C₆H₅COONa + H₂O + CO₂.
The gas evolved is y = CO₂ with molar mass 44 g/mol.
Therefore, molar mass of x + molar mass of y = 2 + 44 = 46.
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This is a previous-year question from JEE Main 2026, covering the Alcohols Phenols and Ethers chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.