JEE Main 2015ChemistryChemical KineticsEasyMCQ

JEE Main 2015 — Chemical Kinetics Question with Solution

JEE Main 2015 (11 Apr Online)

Question

A+2B→C , the rate equation for the reaction is given as

Rate =k[A][B]

If the concentration of A is kept the same but that of B is doubled what will happen to the rate itself?

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Show full solutionCorrect option: A
Correct answer
ADoubled

Step-by-step explanation

The order of the overall reaction is 2.

 Rate =k[A][B]=R

R'=k[A][2B]

RR'=k[A][B]k[A][2B]=k[A][B]2k[A][B]

⇒2R=R' i.e, rate become doubles.

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About this question

This is a previous-year question from JEE Main 2015, covering the Chemical Kinetics chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.