JEE Main 2022ChemistryChemical KineticsMediumNumerical

JEE Main 2022 — Chemical Kinetics Question with Solution

JEE Main 2022 (28 Jun Shift 1)

Question

For a first order reaction A→B, the rate constant, k=5.5×10-14 s-1. The time required for 67% completion of reaction is x×10-1 times the half life of reaction. The value of x is Nearest integer) (Given : log3=0.4771)

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Show full solutionCorrect answer: 16
Correct answer
16

Step-by-step explanation

For first order reaction, t=2.303klogA0At

Now, t67%=2.303klogA0.33A

& t50=2.303klogA0.5A

t67%=1kln11-0.67=t1/2ln2×ln11-23

⇒t67%=1.585×t1/2

X×10-1=1.585

⇒X=15.85

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About this question

This is a previous-year question from JEE Main 2022, covering the Chemical Kinetics chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.