JEE Main 2021ChemistryChemical KineticsMediumNumerical

JEE Main 2021 — Chemical Kinetics Question with Solution

JEE Main 2021 (25 Feb Shift 1)

Question

For the reaction, aA+bB→cC+dD, the plot of log k v/s 1 T is given below:

The temperature at which the rate constant of the reaction is 10-4 s-1 is _____ K.
(Rounded-off to the nearest integer) [Given : The rat5e constant of the reaction is 10-5 s-1 at 500 K.]

Enter your answer

Show full solutionCorrect answer: 526
Correct answer
526

Step-by-step explanation

log k=log A-Ea2.303RT

Slope= Ea 2.303R=10,000

logk2 k1=Ea2.303R1 T1-1 T2

log10-410-5=10,0001500-1 T2

log10-410-5=10,0001500-1 T2

T2=526.31≃526 K

Hence answer is 526

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About this question

This is a previous-year question from JEE Main 2021, covering the Chemical Kinetics chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.