JEE Main 2019ChemistryChemical KineticsMediumMCQ

JEE Main 2019 — Chemical Kinetics Question with Solution

JEE Main 2019 (10 Jan Shift 1)

Question

Consider the given plots for a reaction obeying Arrhenius equation (0°C<T<300°C): ( K and Ea are rate constant and activetion energy, respectively )

(I) 

(II) 

Choose an option

Show full solutionCorrect option: D
Correct answer
DBoth I and II are correct

Step-by-step explanation

K=Ae-Ea/RT

K  decreases exponentially with Ea

∴ The first graph is correct.

But temperature is given in  oC 
So,  K≠0 at 0oC.

∴  For temperature between 0oCand 300oC, the graph will come like (II)

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About this question

This is a previous-year question from JEE Main 2019, covering the Chemical Kinetics chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.